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Force Calculator: Newton’s Second Law, Friction, Tension, Centripetal, Buoyancy and Coulomb’s Law

The Force Calculator: Newton’s Second Law, Friction, Tension, Centripetal, Buoyancy and Coulomb’s Law works out force with F = ma, weight, friction and its coefficient, rope tension, centripetal force, buoyancy or Coulomb's law, in newtons and pounds-force.

Quick Answer: By Newton’s second law, a 10 kg mass accelerating at 2 m/s² needs a net force of 20 N (4.49618 lbf). Choose another force law to get friction, rope tension, centripetal force, buoyancy or the Coulomb force between two charges.

Assumptions

Computed

Preset scenarios

Result
20 N
Force in newtons
20 N
Force in pounds-force
4.49618 lbf
Mass that weighs the same
2.03943 kg
Working
10 kg × 2 m/s²
Electric field of q₁ at r
Only in Coulomb’s law mode
Electric potential of q₁ at r
Only in Coulomb’s law mode

Coulomb force between two 1 µC charges by distance

Download CSV
Each row is this calculator run in Coulomb’s law mode with two +1 µC charges at the distance in the first column, using k = 1/(4πε₀) from the 2022 CODATA permittivity. Values are rounded to six significant figures.
Distance (cm)ForceField of one chargePotential of one charge
189.8755 N89,875,500 N/C898,755 V
222.4689 N22,468,900 N/C449,378 V
53.59502 N3,595,020 N/C179,751 V
100.898755 N898,755 N/C89,875.5 V
200.224689 N224,689 N/C44,937.8 V
500.0359502 N35,950.2 N/C17,975.1 V
1000.00898755 N8,987.55 N/C8,987.55 V

This table and its CSV are free to reuse with a link to this page, CC BY 4.0.

Force Calculator: Newton’s Second Law, Friction, Tension, Centripetal, Buoyancy and Coulomb’s Law: Result 20 N (Force law: Newton’s second law (F = ma); Mass (m): 10; Mass unit: kilograms; Acceleration (a), m/s²: 2).

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A one-page summary of this calculator's default example, drawn from the same calculation as the result above.

The infographic is free to reuse with a link to this page, CC BY 4.0.

Illustration of a crate hanging from a pulley on a wooden beam beside a metal sphere floating in a glass bowl of water
Quick Answer: By Newton’s second law, a 10 kg mass accelerating at 2 m/s² needs a net force of 20 N (4.49618 lbf). Choose another force law to get friction, rope tension, centripetal force, buoyancy or the Coulomb force between two charges.

What does this calculator do?

This force calculator puts the force laws of an introductory physics course in one place. Pick a law, fill in the boxes it uses, and it returns the force in newtons and pounds-force.

It also gives the mass that would weigh the same, and the intermediate figure the law depends on, such as the normal force for friction or the centripetal acceleration on a curve.

The laws covered are Newton’s second law (F = ma), weight (F = mg), kinetic friction (F = μN) and the coefficient of friction from a measured force, the tension in a rope holding a hanging mass, centripetal force (F = mv²/r), the buoyant force of Archimedes’ principle (F = ρVg) and Coulomb’s law for two point charges (F = kq₁q₂/r²). In Coulomb mode it also reports the electric field and electric potential of the first charge at the same distance.

Two constants carry the numbers. Standard gravity is g = 9.80665 m/s², exact by definition and listed by NIST in the CODATA tables. The Coulomb constant k = 1/(4πε₀) is computed from the vacuum electric permittivity ε₀ = 8.8541878188 × 10⁻¹² F/m, the 2022 CODATA value NIST publishes. That gives k = 8.987551786 × 10⁹ N·m²/C², the figure shown in the working line. Masses, volumes, charges and distances are converted to SI units before any formula runs.

Using the Force Calculator

  1. Choose the force law from the first menu.
  2. Fill in the boxes that law reads. Only the boxes that law uses are shown; switch laws and the others come back with the values you left in them.
  3. Pick units where a menu is offered: kilograms, grams or pounds for mass; litres, millilitres, cubic metres, cubic feet or US gallons for volume; coulombs down to picocoulombs or elementary charges for charge; metres down to ångströms for the distance between charges.
  4. Read the force at the top. The cards below give it in newtons and pounds-force, the equivalent mass, and the working.

The six preset buttons load one example of each common law, from a cart being pushed to two charges 10 cm apart.

How is this calculated?

  1. Convert to SI. Mass goes to kilograms, volume to cubic metres, charge to coulombs and distance to metres, using exact unit definitions (1 lb is 0.45359237 kg, 1 US gallon is 231 cubic inches, one elementary charge is 1.602176634 × 10⁻¹⁹ C).
  1. Apply the chosen law. Each mode is one formula, with g = 9.80665 m/s²:

F = ma; F_weight = mg

F_friction = μN, N = mg; μ = F/N

T = m (g + a); F_c = mv²/r

F_b = ρ_fluid V g; F = k q₁q₂/r², k = 1/4πε₀

  1. Friction uses a level surface. The normal force N is taken as the weight, m × g, which is true when the surface is flat and nothing else presses down. The coefficient mode divides the force you measured by that same normal force.
  1. Tension takes upward as positive. A load being lifted and speeding up has a positive acceleration and the rope pulls harder than the weight. A load being lowered and speeding up has a negative one. If the downward acceleration is larger than g, a rope would have to push, so the calculator says so instead of returning a negative tension.
  1. Buoyancy reads the fluid density. Fresh water is pure water at 20 °C, 998.2067 kg/m³, from the CIPM formula for the density of water. For any other fluid, the density you type is used.
  1. Coulomb’s law keeps the sign. A positive product of charges means repulsion and a negative one attraction. The headline shows the size of the force and names its direction. The field and potential of q₁ at the same distance use the same constant:

E = k q₁/r²; V = k q₁/r

  1. Convert back and round. The force is converted to pounds-force (1 lbf is 4.4482216152605 N) and divided by g for the equivalent mass. Results are rounded half up to six significant figures; the coefficient of friction is shown to four.

Worked Example

The default inputs push a 10 kg cart with a net acceleration of 2 m/s²:

  1. F = m × a = 10 × 2 = 20 N.
  2. In pounds-force: 20 ÷ 4.4482216152605 = 4.49618 lbf.
  3. Equivalent mass: 20 ÷ 9.80665 = 2.03943 kg, so the push equals the weight of about two kilograms.

The other presets work the same way:

  • Friction: a 10 kg crate on a level floor has a normal force of 98.0665 N. With μ = 0.3, the force to keep it sliding is 29.42 N.
  • Tension: hoisting 50 kg while speeding up at 2 m/s² puts 590.333 N in the rope, made of the 490.333 N weight plus 100 N to accelerate it.
  • Centripetal: a 1,200 kg car at 20 m/s on a 50 m radius bend needs 9,600 N of sideways grip, a centripetal acceleration of 8 m/s².
  • Buoyancy: a 2 litre object fully under fresh water is pushed up with 19.5781 N.
  • Coulomb: two +1 µC charges 10 cm apart repel with 0.898755 N.

Coulomb’s Law Formula

Coulomb’s law gives the electric force between two point charges: F = k q₁ q₂ / r². The force grows with each charge and falls with the square of the distance, so doubling the gap cuts the force to a quarter. The reference table on this page shows it for two 1 µC charges: 89.8755 N at 1 cm, 22.4689 N at 2 cm and 0.898755 N at 10 cm.

The electric force formula is often written with ε₀ instead of k: F = q₁q₂ / (4πε₀r²). The two are the same thing. Since the 2019 redefinition of the SI, ε₀ is a measured quantity rather than an exact one, which is why k is quoted to ten significant figures here and not as a closed number.

Electric Potential Formulas

Two formulas cover most course problems. The potential of a single point charge at distance r is V = kq / r, measured from zero at infinity, and the potential energy of a pair of charges is U = kq₁q₂ / r. The calculator gives the first one for q₁ in Coulomb mode: a 1 µC charge produces 89,875.5 V at 10 cm. Multiply that potential by the second charge to get the pair’s potential energy in joules.

What Is the Formula for Tension in Physics?

For a single rope holding a mass that moves straight up or down, T = m(g + a), with a positive when the acceleration is upward. At rest or at a steady speed, the tension is just the weight.

Pulleys, ropes at angles and two-body problems such as an Atwood machine need the same idea applied to each body in turn, which this calculator does not set up for you.

What does this calculator not account for?

  • Inclines and angled pulls. Friction mode assumes a level surface, so the normal force is the full weight. On a slope of angle θ the normal force is mg cos θ.
  • Static friction. The friction mode is kinetic friction, for a surface already sliding. The force to start an object moving is usually higher.
  • Multiple forces at once. Each mode is one law. Net force problems with several forces need them added as vectors first, then F = ma.
  • Partly submerged objects. Buoyancy uses the volume you enter as the displaced volume. For a floating object, enter only the part below the surface.
  • Charges that are not points. Coulomb’s law here is for point charges or spheres measured centre to centre, in a vacuum. In water or another medium the force is smaller by the material’s relative permittivity.
  • Local gravity. Standard gravity is a defined value; real gravity varies by a few parts in a thousand across the Earth.

What mistakes do people make with this?

  • Using grams in F = ma. A newton is a kilogram metre per second squared. Entering 500 for half a kilogram gives a force 1,000 times too large unless the mass unit is set to grams.
  • Forgetting the micro. Course problems give charges in microcoulombs or nanocoulombs. Typing 1 with the unit left on coulombs makes the force a trillion times too big for two charges.
  • Using diameter as the radius. Centripetal force divides by the radius of the circle.
  • Confusing mass and weight. Mass is in kilograms; weight is a force in newtons. A 10 kg mass weighs 98.0665 N.
  • Squaring the wrong thing. In Coulomb’s law only the distance is squared; in centripetal force only the speed is.

Frequently Asked Questions

How do I calculate the coefficient of friction?

Measure the force needed to keep an object sliding at a steady speed and divide it by the normal force. On a level surface the normal force is the weight. Choose the coefficient mode, enter the mass and the measured force, and the calculator divides them: 29.42 N on a 10 kg mass gives μ = 0.3.

How do you calculate centripetal force?

Multiply the mass by the square of the speed and divide by the radius: F = mv²/r. Speed must be in metres per second and the radius in metres for the answer to come out in newtons.

What is the buoyancy force formula?

The buoyant force equals the weight of fluid displaced: F = ρVg, with ρ the fluid density, V the submerged volume and g gravity. An object floats when this force can match its weight before it is fully under.

Why does the calculator show an equivalent mass?

It answers the question people often mean when they ask how strong a force is: what would weigh this much? The force is divided by standard gravity, so 9,600 N corresponds to the weight of 978.928 kg.

Is the Coulomb constant exactly 9 × 10⁹?

No, that is a rounded classroom value. The calculator computes k from the CODATA value of ε₀, which gives 8.987551786 × 10⁹ N·m²/C². The rounded value makes answers about 0.14% too high.

Does the calculator handle negative charges?

Yes. Enter a negative number for a negative charge. Opposite signs give an attractive force and like signs a repulsive one; the headline names which.

Sources

Did this calculator answer your question?

How this calculator is tested

This calculator is checked by 10 automated test cases: specific inputs whose correct result is known in advance, and rules the output must always obey. They run on every change to the site. See the testing and corrections policy.

Show the test cases
  • Default: F = ma, 10 kg at 2 m/s² is 20 N
  • weight of 10 kg is 98.0665 N; 1 lb weighs 1 lbf
  • friction: 0.3 x 98.0665 N = 29.42 N (to six figures)
  • coefficient of friction: 29.42 N on 10 kg is 0.3
  • tension: 50 kg hoisted at 2 m/s² is 590.333 N
  • centripetal: 1,200 kg at 20 m/s on a 50 m radius is 9,600 N
  • buoyancy: 2 L in fresh water is 19.5781 N; in a 1000 kg/m³ fluid 19.6133 N
  • Coulomb: two 1 µC charges 10 cm apart repel with 0.898755 N
  • Coulomb at atomic scale: electron and proton 0.529 angstrom apart
  • the inverse square: doubling the distance quarters the force

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